Trong các đẳng thức sau đẳng thức nào sai?

A. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqaMPhvLHfij5gC1rhimfMBNvxyNvgaCLMB0XfBP1 % wA0n3x7btFEThxMjxyJThxWLgi9TNm913ECnxAUbcECrxz4r3EK1hE % 9WvAUrhxSLwBPr3CFThxMjxyJThxWLgi9TNm91Nx7XfCPbsF7X1CP5 % gi0XfDLHhD7rwF01xFamXvP5wqSXMqHnxAJn0BKvguHDwzZbqefqvA % Tv2CG4uz3bIuV1wyUbqedmvETj2BSbqefm0B1jxALjhiov2Daebbnr % fifHhDYfgasaacH8YjY-vipgYlh9vqqj-hEeeu0xXdbba9frFj0-Oq % Ffea0dXdd9vqai-hGuQ8kuc9pgc9q8qqaq-dir-f0-yqaiVgFr0xfr % -xfr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaaeaaaaaaaa % a8qadaWdXbWdaeaapeGaci4CaiaacMgacaGGUbGaamiEaiaabsgaca % WG4bGaeyypa0Zaa8qCa8aabaWdbiGacohacaGGPbGaaiOBaiaadsha % caqGKbGaamiDaaWcpaqaa8qadaWcaaWdaeaapeGaeqiWdahapaqaa8 % qacaaIYaaaaaWdaeaapeGaeqiWdahaniabgUIiYdaal8aabaWdbiaa % icdaa8aabaWdbmaalaaapaqaa8qacqaHapaCa8aabaWdbiaaikdaaa % aaniabgUIiYdaaaa!80E1! \int\limits_0^{\frac{\pi }{2}} {\sin x{\rm{d}}x = \int\limits_{\frac{\pi }{2}}^\pi {\sin t{\rm{d}}t} } \)

B. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqaMrgvLHfij5gC1rhimfMBNvxyNvgaCLMB0XfBP1 % wA0n3x7btFEThxMjxyJThxWLgi9TNm913ECnxAUbcECrxz4r3EK1hE % 9WvAUrhxSLwBPr3CFThm951EX03ECrxz4r3EK1hE91hatCvAUfeBSj % uyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gB % aerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVCI8FfYJH8YrFf % euY-Hhbbf9v8qqaqFr0xc9pk0xbba9q8WqFfeaY-biLkVcLq-JHqpe % peea0-as0Fb9pgeaYRXxe9vr0-vr0-vqpWqaaeaabiGaciaacaqabe % aadaqaaqaaaOqaaabaaaaaaaaapeWaa8qCa8aabaWdbiGacohacaGG % PbGaaiOBaiaadIhacaqGKbGaamiEaiabg2da9maapehapaqaa8qaca % qGKbGaamiEaaWcpaqaa8qacaaIWaaapaqaa8qacaaIXaaaniabgUIi % Ydaal8aabaWdbiaaicdaa8aabaWdbmaalaaapaqaa8qacqaHapaCa8 % aabaWdbiaaikdaaaaaniabgUIiYdaaaa!7156! \int\limits_0^{\frac{\pi }{2}} {\sin x{\rm{d}}x = \int\limits_0^1 {{\rm{d}}x} } \)

C. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqaMDhvLHfij5gC1rhimfMBNvxyNvgaCLMB0XfBP1 % wA0n3x7btFEThxMjxyJThxWLgi9TNm913ECnxAUbcECrxz4r3EK1hE % 9WvAUrhxSLwBPr3CFThm951ECzMCHn2ECbxAG03EY0xF7X1yVnhi0X % fDLHhD7rwF01xFamXvP5wqSXMqHnxAJn0BKvguHDwzZbqefqvATv2C % G4uz3bIuV1wyUbqedmvETj2BSbqefm0B1jxALjhiov2DaebbnrfifH % hDYfgasaacH8YjY-vipgYlh9vqqj-hEeeu0xXdbba9frFj0-OqFfea % 0dXdd9vqai-hGuQ8kuc9pgc9q8qqaq-dir-f0-yqaiVgFr0xfr-xfr % -xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaaeaaaaaaaaa8qa % daWdXbWdaeaapeGaci4CaiaacMgacaGGUbGaamiEaiaabsgacaWG4b % Gaeyypa0Zaa8qCa8aabaWdbiGacogacaGGVbGaai4CaiaadshacaqG % KbGaamiDaaWcpaqaa8qacaaIWaaapaqaa8qadaWcaaWdaeaapeGaeq % iWdahapaqaa8qacaaIYaaaaaqdcqGHRiI8aaWcpaqaa8qacaaIWaaa % paqaa8qadaWcaaWdaeaapeGaeqiWdahapaqaa8qacaaIYaaaaaqdcq % GHRiI8aaaa!7EAC! \int\limits_0^{\frac{\pi }{2}} {\sin x{\rm{d}}x = \int\limits_0^{\frac{\pi }{2}} {\cos t{\rm{d}}t} } \)

D. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqaMrkvLHfij5gC1rhimfMBNvxyNvgaCLMB0XfBP1 % wA0n3x7XLzYf2y7XfCPbsF7ztF951ECzMCHn2ECbxAG03EY0xF7T3E % CnxAUbsFETNm91hECrxz4r3EK1hE9WfBLzgDUacxMjxyJT3E7X1CP5 % gi951EZ0xF413E41hiCjxANHgD891ECzMCHn2ECbxAG03E20xFEThx % MjxyJThxWLgi9TNm91xFamXvP5wqSXMqHnxAJn0BKvguHDwzZbqefq % vATv2CG4uz3bIuV1wyUbqedmvETj2BSbqefm0B1jxALjhiov2Daebb % nrfifHhDYfgasaacH8YjY-vipgYlh9vqqj-hEeeu0xXdbba9frFj0- % OqFfea0dXdd9vqai-hGuQ8kuc9pgc9q8qqaq-dir-f0-yqaiVgFr0x % fr-xfr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaaeaaaaaa % aaa8qadaWdXbWdaeaapeGaci4CaiaacMgacaGGUbWdamaaCaaaleqa % baWdbiaaikdaaaGccaWG4bGaaeizaiaadIhacqGH9aqpdaabcaWdae % aapeWaaSaaa8aabaWdbiGacohacaGGPbGaaiOBa8aadaahaaWcbeqa % a8qacaaIZaaaaOGaamiEaaWdaeaapeGaamiEaaaaaiaawIa7a8aada % qhaaWcbaWdbmaalaaapaqaa8qacqaHapaCa8aabaWdbiaaiAdaaaaa % paqaa8qadaWcaaWdaeaapeGaeqiWdahapaqaa8qacaaIYaaaaaaaa8 % aabaWdbmaalaaapaqaa8qacqaHapaCa8aabaWdbiaaiAdaaaaapaqa % a8qadaWcaaWdaeaapeGaeqiWdahapaqaa8qacaaIYaaaaaqdcqGHRi % I8aaaa!95B0! \int\limits_{\frac{\pi }{6}}^{\frac{\pi }{2}} {{{\sin }^2}x{\rm{d}}x = \left. {\frac{{{{\sin }^3}x}}{x}} \right|_{\frac{\pi }{6}}^{\frac{\pi }{2}}} \)

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Môn: Toán Lớp 12

Chủ đề: Nguyên Hàm - Tích Phân Và Ứng Dụng

Bài: Nguyên hàm

Lời giải:

Báo sai

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