Cho các sơ đồ phản ứng:
\(\begin{array}{l} Glyxin\mathop \to \limits^{ + NaOH} X\mathop \to \limits^{ + HCl\,{\rm{d}}u} Y(1)\\ Glyxin\mathop \to \limits^{ + HCl} Z\mathop \to \limits^{ + NaOH\,{\rm{d}}u} T(2) \end{array}\)
Y và T lần lượt là
Suy nghĩ và trả lời câu hỏi trước khi xem đáp án
Lời giải:
Báo sai*Sơ đồ (1):
\(\begin{array}{l} {H_2}NC{H_2}COOH\mathop \to \limits^{ + NaOH} {H_2}NC{H_2}COONa\left( X \right)\mathop \to \limits^{ + HCl\,{\rm{d}}u} Cl{H_3}NC{H_2}COOH\left( Y \right)\\ PTHH:{H_2}NC{H_2}COOH{\rm{ }} + {\rm{ }}NaOH{\rm{ }} \to {\rm{ }}{H_2}NC{H_2}COONa{\rm{ }} + {\rm{ }}{H_2}O{H_2}NC{H_2}COONa{\rm{ }} + {\rm{ }}HCl{\rm{ }} \to \;Cl{H_3}NC{H_2}COOH\; + {\rm{ }}NaCl \end{array}\)
*Sơ đồ (2):
\(\begin{array}{l} {H_2}NC{H_2}COOH\mathop \to \limits^{ + HCl} Cl{H_3}NC{H_2}COOH\left( Z \right)\mathop \to \limits^{ + NaOH\,{\rm{d}}u} {H_2}NC{H_2}COONa\left( T \right)\\ PTHH:{H_2}NC{H_2}COOH{\rm{ }} + {\rm{ }}HCl{\rm{ }} \to {\rm{ }}Cl{H_3}NC{H_2}COOH\;Cl{H_3}NC{H_2}COOH{\rm{ }} + {\rm{ }}NaOH{\rm{ }} \to \;{H_2}NC{H_2}COONa\; + {\rm{ }}{H_2}O{\rm{ }} + {\rm{ }}NaCl \end{array}\)
