Tìm x biết \(\begin{array}{l} 3\frac{1}{2} + x + \frac{2}{3} = \frac{4}{5} + \frac{1}{2} \end{array}\)
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Lời giải:
Báo sai\(\begin{array}{l} 3\frac{1}{2} + x + \frac{2}{3} = \frac{4}{5} + \frac{1}{2}\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x = \frac{4}{5} + \frac{1}{2} - \frac{2}{3} - 3\frac{1}{2}\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x = \frac{4}{5} + \frac{1}{2} - \frac{2}{3} - \left( {3 + \frac{1}{2}} \right)\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x = \frac{4}{5} + \frac{1}{2} - \frac{2}{3} - 3 - \frac{1}{2}\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x = \frac{4}{5} - \frac{2}{3} - 3\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x = \frac{{12}}{{15}} - \frac{{10}}{{15}} - 3\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x = \frac{2}{{15}} - 3 = \frac{{ - 43}}{{15}} \end{array}\)