Tìm x biết \(\begin{array}{l} 4x - \frac{1}{3} + \frac{5}{2}x + \frac{1}{2} = \frac{5}{4} \end{array}\)
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Lời giải:
Báo sai\(\begin{array}{l} 4x - \frac{1}{3} + \frac{5}{2}x + \frac{1}{2} = \frac{5}{4}\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\left( {4x + \frac{5}{2}x} \right) = \frac{5}{4} - \left( { - \frac{1}{3} + \frac{1}{2}} \right)\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x\left( {4 + \frac{5}{2}} \right) = \frac{5}{4} - \left( { - \frac{1}{3} + \frac{1}{2}} \right)\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x\left( {4 + \frac{5}{2}} \right) = \frac{5}{4} - \frac{1}{6}\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{{13}}{2}x = \frac{{13}}{{12}}\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x = \frac{{13}}{{12}}:\frac{{13}}{2}\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x = \frac{{13}}{{12}} \cdot \frac{2}{{13}}\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x = \frac{1}{6} \end{array}\)