Tính \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamysaiabg2 % da9maapehabaGaamiEaiaac6cacaaIYaWaaWbaaSqabeaacaWG4baa % aOGaaeizaiaadIhaaSqaaiaaicdaaeaacaaIYaaaniabgUIiYdaaaa!4129! I = \int\limits_0^2 {x{{.2}^x}{\rm{d}}x} \)
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Lời giải:
Báo sai\(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamysaiabg2 % da9maapehabaGaamiEaiaac6cacaaIYaWaaWbaaSqabeaacaWG4baa % aOGaamizaiaadIhaaSqaaiaaicdaaeaacaaIYaaaniabgUIiYdGccq % GH9aqpdaabcaqaamaalaaabaGaamiEaiaac6cacaaIYaWaaWbaaSqa % beaacaWG4baaaaGcbaGaciiBaiaac6gacaaIYaaaaaGaayjcSdWaa0 % baaSqaaiaaicdaaeaacaaIYaaaaOGaeyOeI0Yaa8qCaeaadaWcaaqa % aiaaikdadaahaaWcbeqaaiaadIhaaaaakeaaciGGSbGaaiOBaiaaik % daaaGaamizaiaadIhaaSqaaiaaicdaaeaacaaIYaaaniabgUIiYdGc % cqGH9aqpdaabcaqaamaalaaabaGaaGioaaqaaiGacYgacaGGUbGaaG % OmaaaacqGHsisldaWcaaqaaiaaikdadaahaaWcbeqaaiaadIhaaaaa % keaaciGGSbGaaiOBamaaCaaaleqabaGaaGOmaaaakiaaikdaaaaaca % GLiWoadaqhaaWcbaGaaGimaaqaaiaaikdaaaGccqGH9aqpdaWcaaqa % aiaaiIdaaeaaciGGSbGaaiOBaiaaikdaaaGaeyOeI0YaaSaaaeaaca % aIZaaabaGaciiBaiaac6gadaahaaWcbeqaaiaaikdaaaGccaWG4baa % aaaa!6F6A! I = \int\limits_0^2 {x{{.2}^x}dx} = \left. {\frac{{x{{.2}^x}}}{{\ln 2}}} \right|_0^2 - \int\limits_0^2 {\frac{{{2^x}}}{{\ln 2}}dx} = \left. {\frac{8}{{\ln 2}} - \frac{{{2^x}}}{{{{\ln }^2}2}}} \right|_0^2 = \frac{8}{{\ln 2}} - \frac{3}{{{{\ln }^2}x}}\)