Thuỷ phân 324 gam tinh bột với hiệu suất phản ứng là 75%, khối lượng glucozơ thu được là
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Lời giải:
Báo sai\(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeaacaGaaiaabeqaamaabaabaaGceaqabeaadaqada % qaaiaadoeadaWgaaWcbaGaaGOnaaqabaGccaWGibWaaSbaaSqaaiaa % igdacaaIWaaabeaakiaad+eadaWgaaWcbaGaaGynaaqabaaakiaawI % cacaGLPaaadaWgaaWcbaGaamOBaaqabaGccqGHRaWkcaWGUbGaamis % amaaBaaaleaacaaIYaaabeaakiaad+eacqGHsgIRcaWGUbGaam4qam % aaBaaaleaacaaI2aaabeaakiaadIeadaWgaaWcbaGaaGymaiaaikda % aeqaaOGaam4tamaaBaaaleaacaaI2aaabeaaaOqaaiaaikdacaGGUa % GaaiOlaiaac6cacaGGUaGaaiOlaiaac6cacaGGUaGaaiOlaiaac6ca % caGGUaGaaiOlaiaac6cacaGGUaGaaiOlaiaac6cacaGGUaGaaiOlai % aac6cacaGGUaGaaiOlaiaac6cacaGGUaGaaiOlaiaac6cacaGGUaGa % aiOlaiaac6cacaGGUaGaaiOlaiaac6cacaGGUaGaaiOlaiaac6caca % GGUaGaaiOlaiaac6cacaGGUaGaaiOlaiaac6cacaGGUaGaaiOlaiaa % c6cacaaIYaaabaGaeyOKH4QaamyBamaaBaaaleaacaWGdbWaaSbaaW % qaaiaaiAdaaeqaaSGaamisamaaBaaameaacaaIXaGaaGOmaaqabaWc % caWGpbWaaSbaaWqaaiaaiAdaaeqaaaWcbeaakiabg2da9iaaikdaca % GGUaGaaGymaiaaiIdacaaIWaGaaiOlaiaaiEdacaaI1aGaaiyjaiab % g2da9iaaikdacaaI3aGaaGimaiaadEgacaWGHbGaamyBaaaaaa!8143! \begin{gathered} {\left( {{C_6}{H_{10}}{O_5}} \right)_n} + n{H_2}O \to n{C_6}{H_{12}}{O_6} \hfill \\ 2..........................................2 \hfill \\ \to {m_{{C_6}{H_{12}}{O_6}}} = 2.180.75\% = 270gam \hfill \\ \end{gathered} \)
Đề thi thử tốt nghiệp THPT QG môn Hóa năm 2020
Trường THPT Hậu Lộc 4 Thanh Hóa lần 2