Cho dãy số \((u_n)\) với \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGceaqabeaadaGaba % abaeqabaGaamyDamaaBaaaleaacaaIXaaabeaakiabg2da9iaaikda % aeaacaWG1bWaaSbaaSqaaiaad6gacqGHRaWkcaaIXaaabeaakiabgk % HiTiaadwhadaWgaaWcbaGaamOBaaqabaGccqGH9aqpcaaIYaGaamOB % aiabgkHiTiaaigdaaaGaay5Eaaaabaaaaaa!45F6! \begin{array}{l} \left\{ \begin{array}{l} {u_1} = 2\\ {u_{n + 1}} - {u_n} = 2n - 1 \end{array} \right.\\ \end{array}\). Số hạng tổng quát \(u_n\) của dãy số là số hạng nào dưới đây?
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Lời giải:
Báo saiTa có:\(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaiqaaqaabe % qaaiaadwhadaWgaaWcbaGaaGymaaqabaGccqGH9aqpcaaIYaaabaGa % amyDamaaBaaaleaacaaIYaaabeaakiabg2da9iaadwhadaWgaaWcba % GaaGymaaqabaGccqGHRaWkcaaIXaaabaGaamyDamaaBaaaleaacaaI % Zaaabeaakiabg2da9iaadwhadaWgaaWcbaGaaGOmaaqabaGccqGHRa % WkcaaIZaaabaGaaiOlaiaac6cacaGGUaaabaGaamyDamaaBaaaleaa % caWGUbaabeaakiabg2da9iaadwhadaWgaaWcbaGaamOBaiabgkHiTi % aaigdaaeqaaOGaey4kaSIaaGOmaiaad6gacqGHsislcaaIZaaaaiaa % wUhaaaaa!5502! \left\{ \begin{array}{l} {u_1} = 2\\ {u_2} = {u_1} + 1\\ {u_3} = {u_2} + 3\\ ...\\ {u_n} = {u_{n - 1}} + 2n - 3 \end{array} \right.\) .
Cộng hai vế ta được \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyDamaaBa % aaleaacaWGUbaabeaakiabg2da9iaaikdacqGHRaWkcaaIXaGaey4k % aSIaaG4maiabgUcaRiaaiwdacqGHRaWkcaGGUaGaaiOlaiaac6cacq % GHRaWkdaqadaqaaiaaikdacaWGUbGaeyOeI0IaaG4maaGaayjkaiaa % wMcaaiabg2da9iaaikdacqGHRaWkdaqadaqaaiaad6gacqGHsislca % aIXaaacaOaGaayzkaaWaaWbaaSqabeaacaaIYaaaaaaa!4F22! {u_n} = 2 + 1 + 3 + 5 + ... + \left( {2n - 3} \right) = 2 + {\left( {n - 1} \right)^2}\).