Cho hàm số y = sinx. Chọn câu sai.
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Lời giải:
Báo sai\(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGabmyEayaafa % Gaeyypa0Jaae4yaiaab+gacaqGZbGaamiEaiabg2da9iaabohacaqG % PbGaaeOBamaabmaabaWaaSaaaeaacqaHapaCaeaacaaIYaaaaiabgU % caRiaadIhaaiaawIcacaGLPaaaaaa!4598! y' = {\rm{cos}}x = {\rm{sin}}\left( {\frac{\pi }{2} + x} \right)\)
\(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGabmyEayaaga % Gaeyypa0Jaae4yaiaab+gacaqGZbWaaeWaaeaadaWcaaqaaiabec8a % WbqaaiaaikdaaaGaey4kaSIaamiEaaGaayjkaiaawMcaaiabg2da9i % aabohacaqGPbGaaeOBamaabmaabaGaeqiWdaNaey4kaSIaamiEaaGa % ayjkaiaawMcaaaaa!49C1! y'' = {\rm{cos}}\left( {\frac{\pi }{2} + x} \right) = {\rm{sin}}\left( {\pi + x} \right)\)
\(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGabmyEayaasa % Gaeyypa0Jaae4yaiaab+gacaqGZbWaaeWaaeaacqaHapaCcqGHRaWk % caWG4baacaGLOaGaayzkaaGaeyypa0Jaae4CaiaabMgacaqGUbWaae % WaaeaadaWcaaqaaiaaiodacqaHapaCaeaacaaIYaaaaiabgUcaRiaa % dIhaaiaawIcacaGLPaaaaaa!4A8A! y''' = {\rm{cos}}\left( {\pi + x} \right) = {\rm{sin}}\left( {\frac{{3\pi }}{2} + x} \right)\)
\(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEamaaCa % aaleqabaWaaeWaaeaacaaI0aaacaGLOaGaayzkaaaaaOGaeyypa0Ja % ae4yaiaab+gacaqGZbWaaeWaaeaadaWcaaqaaiaaiodacqaHapaCae % aacaaIYaaaaiabgUcaRiaadIhaaiaawIcacaGLPaaacqGH9aqpcaqG % ZbGaaeyAaiaab6gadaqadaqaaiaaikdacqaHapaCcqGHRaWkcaWG4b % aacaGLOaGaayzkaaaaaa!4DAB! {y^{\left( 4 \right)}} = {\rm{cos}}\left( {\frac{{3\pi }}{2} + x} \right) = {\rm{sin}}\left( {2\pi + x} \right)\)