Tìm tất cả giá trị thực của tham số m để hàm số \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaqcLbAacaWG5b % Gaeyypa0JcdaWcaaqaaKqzGgGaaGymaaGcbaqcLbAacaaIZaaaaiaa % dIhakmaaCaaaleqabaGaaG4maaaajugObiabgkHiTiaaikdacaWGTb % GaamiEaOWaaWbaaSqabeaacaaIYaaaaKqzGgGaey4kaSIaaiikaiaa % d2gacqGHRaWkcaaIZaGaaiykaiaadIhacqGHRaWkcaWGTbGaeyOeI0 % IaaGynaaaa!4EA4! y = \frac{1}{3}{x^3} - 2m{x^2} + (m + 3)x + m - 5\) đồng biến trên R
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Lời giải:
Báo saiTập xác định D = R.
\(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGabmyEayaafa % Gaeyypa0JaamiEamaaCaaaleqabaGaaGOmaaaakiabgkHiTiaaisda % caWGTbGaamiEaiabgUcaRiaad2gacqGHRaWkcaaIZaaaaa!4101! y' = {x^2} - 4mx + m + 3\)
Hàm số đã cho đồng biến trên R \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaeyi1HSTafu % iLdqKbauaacqGH9aqpcaaI0aGaamyBamaaCaaaleqabaGaaGOmaaaa % kiabgkHiTiaad2gacqGHsislcaaIZaGaeyizImQaaGimaaaa!4363! \Leftrightarrow \Delta ' = 4{m^2} - m - 3 \le 0\) \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaeyi1HSTaey % OeI0YaaSaaaeaacaaIZaaabaGaaGinaaaacqGHKjYOcaWGTbGaeyiz % ImQaaGymaaaa!3FDF! \Leftrightarrow - \frac{3}{4} \le m \le 1\) .