Tính đạo hàm của hàm số sau \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2 % da9maakaaabaGaaG4maiaadIhacqGHRaWkcaaIYaGaciiDaiaacgga % caGGUbGaamiEaaWcbeaaaaa!3F39! y = \sqrt {3x + 2\tan x} \)
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Lời giải:
Báo sai\(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiaacE % cacqGH9aqpdaWcaaqaaiaacIcacaaIZaGaamiEaiabgUcaRiaaikda % ciGG0bGaaiyyaiaac6gacaWG4bGaaiykaiaacEcaaeaacaaIYaWaaO % aaaeaacaaIZaGaamiEaiabgUcaRiaaikdaciGG0bGaaiyyaiaac6ga % caWG4baaleqaaaaakiabg2da9maalaaabaGaaG4maiabgUcaRiaaik % dacaGGOaGaaGymaiabgUcaRiGacshacaGGHbGaaiOBamaaCaaaleqa % baGaaGOmaaaakiaadIhacaGGPaaabaGaaGOmamaakaaabaGaaG4mai % aadIhacqGHRaWkcaaIYaGaciiDaiaacggacaGGUbGaamiEaaWcbeaa % aaGccqGH9aqpdaWcaaqaaiaaiwdacqGHRaWkcaaIYaGaciiDaiaacg % gacaGGUbWaaWbaaSqabeaacaaIYaaaaOGaamiEaaqaaiaaikdadaGc % aaqaaiaaiodacaWG4bGaey4kaSIaaGOmaiGacshacaGGHbGaaiOBai % aadIhaaSqabaaaaaaa!6D44! y' = \frac{{(3x + 2\tan x)'}}{{2\sqrt {3x + 2\tan x} }} = \frac{{3 + 2(1 + {{\tan }^2}x)}}{{2\sqrt {3x + 2\tan x} }} = \frac{{5 + 2{{\tan }^2}x}}{{2\sqrt {3x + 2\tan x} }}\)